Theory

 

A weighted spring is hung vertically, subjected to a displacing force, and released.  The motion of its weighted end, plotted as a function of time, resembles that of a simple linear oscillator:

 

h  =  A cos(B t + C) + D

 

where h  is the vertical displacement from a fixed reference

                                                A  is the displacement amplitude

                                                B  the angular frequency [radians per second]

                                                C  is the phase angle [radians]

                                                D  is the relaxed position distance from reference

 

The angular frequency  B  is entertaining.  Its negative square is the ratio of the spring’s endpoint acceleration  a  to its endpoint displacement  x  (where both are functions of time):

 

                        a  =  - B2 h

 

Multiplying both sides by the effective mass  m  of the spring/weight system,

 

                   m a  =  - m B2 h

 

Hooke’s Law relates the vertical spring’s restoring force  F  at any instant to its vertical displacement from relaxed position, by means of the spring constant  k  :

 

                        F  =  - k h

 

Evidently  k  is a constant value that relates a spring system’s mass to its characteristic angular frequency of oscillation:

 

                        k  =  m B2

 

 

Practical concerns

 

We have been trained to recognize  k  as having the unit of force divided by length (newtons per meter in S.I.), which simplifies to mass divided by the square of time ( kg / s2 ).  Since the unit of  B  is radians per second  (s -1 ), then the unit of  (m B2) is  ( kg / s2 ); or, if  cgs  units are used, ( g / s2 ). 

 


Angles and waves

 

The frequency of a rotating angle is expressed in radians per second (s -1).  The y-component of  a unit-circle position vector obeys the time function

           

            y  =  sin t ,

 

so the angular frequency of a sine wave ( B s -1)  equals the frequency of the rotating angle from which it was generated.  In one cycle the rotating angle sweeps out  2 pi  radians, so its corresponding sine wave has periodic frequency  B / (2 pi )  cycles per second, and a cyclic period

 

            T  =  2 pi / B ,

 

where the unit of  T  is seconds (s) .  From the above discussion, we saw the relation between a spring’s effective mass and the angular frequency of its oscillation:

 

            B2  =  k / m

 

Combining these two equations, we get the period of the sine wave generated by an oscillating spring:

 

            T  =  2 pi (m / k) ½

 

Apparently the period is determined only by the spring’s effective mass and its “stiffness”  ( k ).  If  k  for a spring is known, the period of the spring’s oscillation can be calculated from its effective mass.

 

 

Finding the value of k

 

From the above equation we get

 

            k  =  4 pi 2 m / T2

 

With mass in grams and T in seconds, the unit of  k  ( g / s2 ) agrees with the above discussion.  But Hooke’s Law shows

 

            k  =  - F / h

 

and the two expressions are equivalent, as we have seen.  The factor  k   that relates a spring’s effective mass to its oscillation period, is the same  k  that relates a spring’s restoring force to its endpoint displacement from rest position. 

 

We can determine the value of  k  for a spring by hanging various weights on it and measuring its endpoint displacement.  Plotting weight as a function of displacement, the slope of the best-fit line gives the value of  k .  Using linear regression and a t-test, we can construct a confidence interval for our experimentally-derived value of  k  :

 

[Confidence Interval]   =   k  ±  ( t  s / {Sx½} )

 

where  k  is the slope of the regression (best-fit) line

             t   is Student’s test statistic

 s  is the standard deviation of the regression slope

 n  is the number of samples

Sx  is a certain calculated parameter[1]

 

(In determining  k  for our spring, we used the t-value for 90% confidence and 7 degrees of freedom.)

 


Error Analysis

 

In the determination of  k , each of our length measurements was subject to error of  no less than ±  0.1 cm.  These measurement errors correspond to relative errors ranging from 1% (for larger displacements) to 5% (for smaller displacements).  Since we determined  k  by a best-fit slope, a second source of error was in deviation of the data from linearity.  In propagating measurement error through the regression, the confidence intervals for  k  varied like this:

 

Measurement

90% Confidence Interval for  k

Relative error in C.I.

+ 0.1 cm

(9.8    ±  0.1  ) x 103  g / s2

± 1 %

   0    cm

(9.82  ±  0.08) x 103  g / s2

± 0.8 %

-  0.1 cm

(9.83  ±  0.06) x 103  g / s2

± 0.6 %

 

Interestingly, the effect of measurement error on the derived value of  k  was nearly an order of magnitude smaller than the worst-case variation in  k  due to nonlinearity.  The nonlinearity reflects a more conservative estimate of error in the derived value of  k .

 


 

 

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We have described the spring/mass system’s behavior in three ways:

·        A sine wave

·        An acceleration proportional to displacement

·        A force proportional to displacement

 



[1] Sincich, Terry, Statistics By Example, Macmillan Publishing Company, New York, 1993, pp.534-553